From 5fe9cdf06ae86d024a985ba618149bcf6df35cee Mon Sep 17 00:00:00 2001
From: =?UTF-8?q?Martin=20P=C3=A9pin?= <martin.pepin@netcourrier.com>
Date: Tue, 5 Apr 2016 22:31:38 +0200
Subject: [PATCH] update makefile to workwith asciimath, add example

---
 Makefile  | 12 +++++++-----
 asciimath |  2 +-
 notes.md  | 13 ++++++-------
 3 files changed, 14 insertions(+), 13 deletions(-)

diff --git a/Makefile b/Makefile
index f5c2354..4c73b03 100644
--- a/Makefile
+++ b/Makefile
@@ -1,17 +1,15 @@
 SOURCES = $(wildcard *.md)
 OUT = $(SOURCES:.md=.pdf)
 
-HS_FILTERS_NAMES = nice-frac usual-fun
+HS_FILTERS_NAMES =
 PY_FILTERS_NAMES = pandoc-svg.py
-EXT_FILTERS = pandoc-crossref
+EXT_FILTERS = asciimath/pandoc-asciimath
 
 HS_FILTERS = $(addprefix filters/, $(HS_FILTERS_NAMES))
 PY_FILTERS = $(addprefix filters/, $(PY_FILTERS_NAMES))
 FILTERS = $(PY_FILTERS) $(HS_FILTERS) $(EXT_FILTERS)
 
-.SUFFIXES: .hs
-
-all: $(HS_FILTERS) $(OUT)
+all: $(HS_FILTERS) asciimath/pandoc-asciimath $(OUT)
 
 $(OUT):
 	pandoc -S --toc -t latex $(basename $@).md $(addprefix --filter=, $(FILTERS)) -o $@
@@ -19,11 +17,15 @@ $(OUT):
 $(HS_FILTERS):
 	ghc --make $@.hs -o $@	
 
+asciimath/pandoc-asciimath:
+	(cd asciimath; make filter)
+
 clean:
 	rm -f $(OUT)
 	rm -f $(addprefix filters/, $(HS_FILTERS))
 	find . -name "*.pandoc.pdf" -delete
 
 deepclean: clean
+	(cd asciimath; make clean)
 	rm -f $(HS_FILTERS)
 	rm -f filters/*.hi filters/*.o
diff --git a/asciimath b/asciimath
index 00efad2..36146d2 160000
--- a/asciimath
+++ b/asciimath
@@ -1 +1 @@
-Subproject commit 00efad24740eebf51e80c2e5f1f8b8b642d5bb4a
+Subproject commit 36146d2f796dccb07795b2b87a7c98a23e3d0f49
diff --git a/notes.md b/notes.md
index f366418..65ebfe3 100644
--- a/notes.md
+++ b/notes.md
@@ -1,13 +1,8 @@
 ---
 # Metadata
-title: %title%
-author: Lucas Verney
+title: Example
+author: Martin Pépin
 date: \today
-# LaTeX headers
-header-includes:
-    - \usepackage{dsfont}
-    - \usepackage{mathtools}
-    - \renewcommand{\arraystretch}{1.5}
 # Pandoc-crossref options
 cref: True
 chapters: True
@@ -15,3 +10,7 @@ chapters: True
 
 \pagebreak
 
+# Asciimath
+
+Soit $n in NN$, alors on a
+$$ sum_(k=1)^n k^3 = ((n(n+1))/2)^2 $$